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8a^2-34a+21=0
a = 8; b = -34; c = +21;
Δ = b2-4ac
Δ = -342-4·8·21
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-22}{2*8}=\frac{12}{16} =3/4 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+22}{2*8}=\frac{56}{16} =3+1/2 $
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